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The pK Scale

Introduction

In our discussion of conductance, we introduced the term acidity constant, Ka, as a measure of the concentration of hydronium ions produced by the dissociation of a compound when it was dissolved in water. In the case of acetic acid, the acidity constant is given by the expression

Mathematical manipulation yields an alternative form of this equation:

The important point about this equation is the relationship between pKa and the more familiar pH; pH is a measure of the acidity of a solution, i.e. the concentration of hydronium ions, while pKa is a measure of the inherent acidity of a compound, i.e. the tendency of a compound to transfer a proton to a base. These parameters vary in the same way: the lower the pH, the higher the hydronium ion concentration; the lower the pKa the more acidic the compound. We will use the pKa scale to gain insight into the variables that determine the acidity of a compound as well as to develop a system for predicting approximate equilibrium constants for a variety of reactions.

Acid-Base Relationships

Consider the generalized representation of an acid-base reaction shown in Equation 1.

In this reaction, an acid, H-A1, transfers a proton to a base, -:A2, forming a new acid, H-A2 and a new base, -:A1. The species -:A1 is called the conjugate base of H-A1; H-A1 and -:A1 constitute a conjugate acid-base pair. The same terms apply to H-A2 and -:A2.


Exercise 1 Write the expression for Keq for Equation 1.

Exercise 2 Assume you mixed 100 molecules of H-A1 with 100 -:A2 ions. If the value of Keq were 1, at equilibrium the mixture would contain molecules of H-A1 -:A2 ions molecules of H-A2 and -:A1 ions.

Exercise 3 Which is the stronger acid, H-A1 or H-A2? H-A1 H-A2 Neither, they have the same strength.

Exercise 4 If the value of Keq were 10 rather than 1, which compound would be the stronger acid? H-A1 H-A2

Exercise 5 If the value of Keq were 0.1 rather than 1, which compound would be the stronger acid? H-A1 H-A2


When we talk about acid strength, we're talking about the tendency of a compound to transfer a proton to a base. This tendency is related to the relative stability of the acid: compounds with high acid strength are very reactive; they have low stability in comparison to another acid of lower acid strength.

By the same token, if an acid is very reactive, its conjugate base is very non-reactive, i.e. very stable.

In any acid-base equilibrium, the equilibrium will favor the less reactive, more stable compounds. In other words, the equilibrium constant will be greater than 1 whenever the products of the acid-base reaction are more stable than the reactants. In other words, there will always be more of the weaker acid present in the mixture at equilibrium. This means that if the pKa of H-A2 is greater than that of H-A1, the equilibrium constant for Equation 1 will be greater than 1.

Table 1 lists approximate pKa values of a representative group of acids. All the values have been rounded to the nearest whole number. The proton that is transferred is shown in red.

Table 1

pKa Values of Selected "Acids"

Compound

Structure

pKa

Conjugate Base

methane

50

ethene

44

ammonia

38

acetone

19

water

16

methanol

16

phenol

10

acetylacetone

9

acetic acid

5

hydrogen fluoride

3

hydronium ion

-2

hydrogen chloride

-7

hydrogen bromide

-9

hydrogen iodide

-10


Exercise 6 Which of the compounds in Table 1 is the weakest acid? Which is the strongest acid? Which compound has the strongest conjugate base?

Exercise 7 For each of the following acid-base reactions, use the pKa values given in Table 1 to determine whether the value of Keq will be greater than, less than, or equal to 1.

greater

less

equal

greater

less

equal

greater

less

equal

greater

less

equal

It is possible to use the pKa values of two acids that are involved in an acid-base reaction to calculate an approximate value for the equilibrium constant for the reaction. Consider the example illustrated by Equation 2.

The pKa value of methanol is 16 while that of ammonia is 38. Ammonia is a much weaker acid than methanol. The equilibrium constant for Equation 2, therefore, must be greater than 1. Since the difference between the pKa values of methanol and ammonia is 38-16=22, the value of Keq for Equation 2 is approximately 1022. An analysis of this approach is available via the link below.


Exercise 8 Calculate the approximate value of the equilibrium constant for each of the following reactions.

a. Keq =

b. Keq =


pKa Calculations

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